Which ksp is more soluble

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Score on SAT Math. Score on SAT Reading. Score on SAT Writing. What ACT target score should you be aiming for? Since Lead II chloride produces three ions in solution, we can determine its solubility relative to the other three by comparing Ksp values.

Here are the Ksp values for the three salts at 25 degrees Celsius. For silver chloride, it's 1. And for silver iodide, it's 8. When comparing salts that produce the same number of ions, the higher the value of Ksp, the higher the solubility of the salt.

And since silver chloride has the highest Ksp value of these three, silver chloride is the most soluble salts. For some insight into why this is true, let's look at the Ksp expression for silver chloride, which we can get from the balanced equation. The higher the value for Ksp, the higher the concentration of these ions at equilibrium, which means that more of the solid must have dissolved. Therefore, silver chloride has the highest solubility out of these three salts.

Let's say we have some solid calcium fluoride that we add to pure water at 25 degrees Celsius. Our goal is to calculate the Ksp for calcium fluoride at 25 degrees Celsius. The first step is to write out the dissolution equation for calcium fluoride. So 2F- also in aqueous solution. The next step is to use the balanced equation to write the Ksp expression. So here's our expression with 2. Recall that the definition of solubility is the maximum possible concentration of a solute in a solution at a given temperature and pressure.

We can determine the solubility product of a slightly soluble solid from that measure of its solubility at a given temperature and pressure, provided that the only significant reaction that occurs when the solid dissolves is its dissociation into solvated ions, that is, the only equilibrium involved is:.

Calculation of K sp from Equilibrium Concentrations. We began the chapter with an informal discussion of how the mineral fluorite is formed. The known K sp values from the Table above can be used to calculate the solubility of a given compound by following the steps listed below. The K sp of calcium carbonate is 4. The variable will be used to represent the molar solubility of CaCO 3. Therefore, the equilibrium concentrations of each ion are equal to.

The K sp expression can be written in terms of and then used to solve for. The concentration of each of the ions at equilibrium is 6. We can use the molar mass to convert from molar solubility to solubility.